Algebraic Properties. Operators of Finite Rank by B. Booss, D. D. Bleecker.
Exercise 1. For finite-dimensional vector spaces the notion of Fredholm operator is empty, since then every linear map a operator. Moreover, index no longer depends on explicit form map, but only dimensions between which it operates. More precisely, show that T: H → H’ where and are has given by T = dim — H’.KeywordsExact SequenceBetti NumberFredholm OperatorAlgebraic PropertyFinite IndexThese keywords were added machine not authors. This process experimental may be updated as learning algorithm improves.
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